point (0,5), (5,0) and (2,2) form a triangle which is
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Let this triangle be ABC.
A = (0,5)
B = (5,0)
C = (2,2)
The formulae for getting the length of a line is :
L = √(x₁ - x₂) ² + (y₁ - y₂) ²
AB = √(5-0)² + (0 - 5)² = √50
√50 = 7.071 units
BC = √((2 - 5)² + (2 - 0)² = √12
√12 = 3.464 units
AC = √(0 - 2)² + (5 - 2)² = √12
√12 = 3.464 units
From the calculations :
BC = AC
This implies that Triangle ABC is an isosceles triangle.
A = (0,5)
B = (5,0)
C = (2,2)
The formulae for getting the length of a line is :
L = √(x₁ - x₂) ² + (y₁ - y₂) ²
AB = √(5-0)² + (0 - 5)² = √50
√50 = 7.071 units
BC = √((2 - 5)² + (2 - 0)² = √12
√12 = 3.464 units
AC = √(0 - 2)² + (5 - 2)² = √12
√12 = 3.464 units
From the calculations :
BC = AC
This implies that Triangle ABC is an isosceles triangle.
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