Point (2p+1,p-3) lies on the graph of the equation x+2y=3. Find the value of p
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The value of p is 2
Given:
Point (2p+1, p-3) lies on the graph of the equation x+2y=3
To find:
Find the value of p
Solution:
Given that (2p+1, p-3) lies on x+2y=3
Since p lies on x + 2y = 3 then (2p+1,p-3) will must satisfy the given equation
Take x = 2p+1 and y = p-3
⇒ 2p+1 +2 (p-3) =3
⇒ 2p+1 + 2p-6 = 3
⇒ 4p - 5 = 3
⇒ 4p = 8
⇒ p = 2
The value of p = 2
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