Math, asked by lavanyauday8356, 1 year ago

Point (2p+1,p-3) lies on the graph of the equation x+2y=3. Find the value of p

Answers

Answered by brunoconti
2

Answer:

Step-by-step explanation:

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Answered by Dhruv4886
0

The value of p is 2

Given:

Point (2p+1, p-3) lies on the graph of the equation x+2y=3

To find:

Find the value of p

Solution:

Given that (2p+1, p-3) lies on x+2y=3

Since p lies on x + 2y = 3 then (2p+1,p-3) will must satisfy the given equation

Take x = 2p+1 and y = p-3  

⇒  2p+1 +2 (p-3) =3

⇒  2p+1 + 2p-6 = 3

⇒ 4p - 5 = 3

⇒ 4p = 8

⇒ p = 2

The value of p = 2

#SPJ2

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