Question

Point(3, 4) lies on the graph of the equation 3y = k x + 7. The value of k is:1 point
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Answer 1

Answer:

Suppose x=3 and y=4.

3y=kx+7

3(4)=k(3)+7

12=3k+7

12-7=3k

5=3k

k=5/3 Answer

Answer 2

Given data:

The point P (3, 4) lies on the graph of the equation 3y = kx + 7

To find:

The value of k

Step-by-step explanation:

Since P (3, 4) lies on the graph of the equation 3y = kx + 7, then we can say that x = 3 and y = 4 is a solution of the equation

⇒ 3 (4) = k (3) + 7

⇒ 12 = 3k + 7

⇒ 3k = 12 - 7

⇒ 3k = 5

⇒ k = 5/3

Answer: k = 5/3

To find the graph of the given equation for k = 5/3, see the given picture.