Point(3, 4) lies on the graph of the equation 3y = k x + 7. The value of k is:1 point
Answers
Answered by
57
Answer:
Suppose x=3 and y=4.
3y=kx+7
3(4)=k(3)+7
12=3k+7
12-7=3k
5=3k
k=5/3 Answer
Answered by
7
Given data:
The point P (3, 4) lies on the graph of the equation 3y = kx + 7
To find:
The value of k
Step-by-step explanation:
Since P (3, 4) lies on the graph of the equation 3y = kx + 7, then we can say that x = 3 and y = 4 is a solution of the equation
⇒ 3 (4) = k (3) + 7
⇒ 12 = 3k + 7
⇒ 3k = 12 - 7
⇒ 3k = 5
⇒ k = 5/3
Answer: k = 5/3
To find the graph of the given equation for k = 5/3, see the given picture.
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