Question

Point (3,4) lies on the graph of the equation 3y=kx+7. the value of k is

Answer 1

Step-by-step explanation:

let y = 4, x = 3

3y = Kx + 7

3 (4) = k(3) +7

12-7 = 3k

5 = 3k

k = 5/3

Answer 2

The correct answer is $\frac{5}{3}$.

Given: Equation of line = 3y = kx + 7.

Point that lie on this line = (3,4).

To Find: The value of k.

Solution:

As this point lies on the line than it should satisfy the equation of line.

So, putting (3, 4) in 3y = kx + 7.

3 (4) = k (3) + 7

12 = 3k + 7

3k = 5

k =  $\frac{5}{3}$.

Hence, the value of k =  $\frac{5}{3}$.

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