Question

point (3,4) lies on the graph of the equation 3y=kx+7 the value of k is

a. 2/3
b. 5/3
c. 0
d. 3/7

Answer 1

Answer:

answer is supposed to be 5/3

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Answer 2

$\huge\boxed{ { \tt{Solution :)}}}$

Given ,

The point (3,4) lies on the line 3y = kx + 7

∴ Put x = 3 and y = 4 in equation of the line , we get

3(4) = k(3) + 7

12 = 3k + 7

5 = 3k

k = 5/3

Therefore , the correct option is (b)

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