Math, asked by bhupendertyagi1901, 5 months ago

Point(3,4) lies on the graph of the equation 3y=kx+7. what is the value of 7:a.)4/3b.)5/3c.) 3d.)7/3​

Answers

Answered by chawlachawla1100
2

Answer:

Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point. Hence, the value of a is 5/3

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