Question

point (3,7) q(a,b) e(6,8) are collinear where a+b=1 find a and b​

Answer 1

$\frac{a - 3}{b - 7} = \frac{6 - 3}{8 - 7} \\ \\ a - 3 = 3(b - 7) \\ \\ a - 3b + 18 = 0 \\ \\ also \\ \\ a + b = 1 \\ \\ b - 1 - 3b + 18 = 0 \\ \\ b = \frac{17}{2} \\ \\ a = - \frac{15}{2}$

hope it helps