Point (4,1) satisfies to which equation of line ?
(A) x + 2y = 5
(B) x + 2y = -6
(C) x + 2y = 6
(D) x + 2y - 16
Answer is C
Answers
Given : Different equations of line :
(A) x + 2y = 5
(B) x + 2y = -6
(C) x + 2y = 6
(D) x + 2y = 16
To Find :Point (4,1) satisfies to which equation of line
Solution:
Substitute point ( 4 , 1) in Each equation and check whether its satisfy or not
x = 4
y = 1
(A) x + 2y = 5
=> 4 + 2(1) = 6 ≠ 5
Does not satisfy
(B) x + 2y = -6
4 + 2(1) = 6 ≠ - 6
Does not satisfy
(C) x + 2y = 6
4 + 2(1) = 6 = 6
Satisfied
(D) x + 2y = 16
4 + 2(1) = 6 ≠ 1 6
Does not satisfy
Hence Point (4,1) satisfies (C) x + 2y = 6 .
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Given :- Point (4,1) satisfies to which equation of line ?
(A) x + 2y = 5
(B) x + 2y = -6
(C) x + 2y = 6
(D) x + 2y = - 16
Solution :-
checking all given options one by one by putting x = 4 and y = 1 we get,
A) x + 2y = 5
→ 4 + 2 * 1 = 5
→ 4 + 2 = 5
→ 6 = 5 .
since,
→ LHS ≠ RHS .
Point (4,1) does not satisfy x + 2y = 5 .
B) x + 2y = -6
→ 4 + 2 * 1 = -6
→ 4 + 2 = -6
→ 6 = -6 .
since,
→ LHS ≠ RHS .
Point (4,1) does not satisfy x + 2y = -6 .
C) x + 2y = 6
→ 4 + 2 * 1 = 6
→ 4 + 2 = 6
→ 6 = 6 .
since,
→ LHS = RHS .
Therefore, Point (4,1) satisfy x + 2y = 6 .
D) x + 2y = -16
→ 4 + 2 * 1 = -16
→ 4 + 2 = -16
→ 6 = -16 .
since,
→ LHS ≠ RHS .
Point (4,1) does not satisfy x + 2y = -16 .
Hence, (C) is correct option .
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