Point A (–4,1) is in the standard (x,y) coordinate plane. What must be the coordinates
of point B so that the line x = 2 is the perpendicular bisector of AB ?
A. (–6, 1)
B. (–4,–1)
C. (–4, 3)
D. (–2, 1)
E. ( 8, 1)
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As a perpendicular bisector, line x = 2 must be at equal distance from A and B
After locating the points on a cartesian plane, it can be observed that the point is about at a distance of 6 units from line x = 2 and towards the second quadrant. Therefore, B must be located 6 units away from the line, towards the first quadrant.
This makes the point to lie on coordinates (8,1)
After locating the points on a cartesian plane, it can be observed that the point is about at a distance of 6 units from line x = 2 and towards the second quadrant. Therefore, B must be located 6 units away from the line, towards the first quadrant.
This makes the point to lie on coordinates (8,1)
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