point A and B are 110 km away from each other on the highway. A car starts from A and another from B at the same time. if they go in same attractions in meet after 11 hours and if they go and opposite reaction they leave in 1 hours and 6 minutes
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Answered by
51
Let speed of CarA = P km/h
speed of carB = Q km/h
first case :
same interactions means same direction.
we know,
time = distance/speed
for some direction relative speed = (P - Q) km/h
11 = 110/(P - Q)
P - Q = 10 km/h -----(2)
2nd case :
car move opposite direction
so, relative speed = (P + Q) km/h
1+ 6/60 = 110/(P + Q)
P + Q = 100 km/h -----(2)
from equation (1) and (2)
P = 55 km/h and Q = 45 km/h
hence, speed of cars 55km/h and 45 km/h
speed of carB = Q km/h
first case :
same interactions means same direction.
we know,
time = distance/speed
for some direction relative speed = (P - Q) km/h
11 = 110/(P - Q)
P - Q = 10 km/h -----(2)
2nd case :
car move opposite direction
so, relative speed = (P + Q) km/h
1+ 6/60 = 110/(P + Q)
P + Q = 100 km/h -----(2)
from equation (1) and (2)
P = 55 km/h and Q = 45 km/h
hence, speed of cars 55km/h and 45 km/h
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I don't know please answer my question
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