point A and B are 90 km apart from each other on a highway A car starts from A and another from B at the same time if they go in same Direction they meet in 9 hours if they go in opposite direction they meet in 9.7 hours find the speed
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Answered by
40
let 1st car be x
let 2nd car be y
moving from point a and b respectively.
speed of car x= x km/h
speed of cary= y km/h
case1: when they move in the same directions.
they meet in 9hrs
distance by x= 9x
distance by y= 9y
=> 9x-9y=90
x-y=10 (1)
case 2: when they move in opposite direction
they meet after 9.7 hrs
distance by x= 9.7x
distance by y= 9.7y
=> 9.7x+9.7y=90
x+y=9.27.. (2)
on equating and solving the two equations, you'll get your desired answer.
let 2nd car be y
moving from point a and b respectively.
speed of car x= x km/h
speed of cary= y km/h
case1: when they move in the same directions.
they meet in 9hrs
distance by x= 9x
distance by y= 9y
=> 9x-9y=90
x-y=10 (1)
case 2: when they move in opposite direction
they meet after 9.7 hrs
distance by x= 9.7x
distance by y= 9.7y
=> 9.7x+9.7y=90
x+y=9.27.. (2)
on equating and solving the two equations, you'll get your desired answer.
Neelpatel24:
i have say 9 / 7 is there
Answered by
8
Let the speed of the first car which starts from A = x km /hr
Speed of the second car which starts from B = y km / hr
Time = distance / speed
Distance between two places A andB are 80km d = 80 km
i ) if the cars move in same direction
Relative speed of them = ( x + y )km/hr
Time = 8hr
d = 80km
8 = 80 / ( x + y )
x + y = 80 / 8
x + y = 10 ------( 1 )
ii ) if two cars moving opposite direction, Relative speed = ( x - y ) km / hr
Time = 1 hr 20 minutes
= ( 1 + 20 / 60 ) hr
= ( 80/60)
= 4/3 hr
d = 80km
4/3 = 80 / ( x -y )
x -y = ( 80 × 3 ) / 4
x - y = 60-----( 2 )
Add ( 1 ) and ( 2 ) , we get
2x = 70
x = 35
Put x = 35 in ( 1 ) we get ,
y = 25
so,
Speed of the first car = x = 35km/hr
Speed of the second car = 25km /hr
hope it helps you mark as brainliest please
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