Point a and b lie on same side of line xy. if ad perpendiculer to xy and be perpendicular to xy and c is midpoint of ab prove cd=ce
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CD = CE by CPCT rule.
Constructing a perpendicular as C TO DE at Z.
In the figure, the transversal AB will make an equal transversal with AD, CZ, BE
Thus, it will also make an equal intercept with DE .
Hence, in ΔCDZ and ΔCEZ
DZ = DE
∠CZD = ∠CZE ( By construction )
CZ = CZ ( Common Side )
Therefore, ΔCDZ ≅ ΔCEZ ( By SAS congruency )
SO CD = CE by the CPCT rule.
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∆CDZ = ∆CEZ {BY SAS}
CD = CE {C.P.C.T}
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