point A is at (-1,8) and point B is at (7,3) what is the midpoint of line segment AB
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Answer:
The formula of a midpoint of line segment AB:
(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2})(
2
x
A
+x
B
;
2
y
A
+y
B
)
We have A(-1, 8) and B(7, 3). Substitute:
\begin{gathered}x=\dfrac{-1+7}{2}=\dfrac{6}{2}=3\\\\y=\dfrac{8+3}{2}=\dfrac{11}{2}=5.5\end{gathered}
x=
2
−1+7
=
2
6
=3
y=
2
8+3
=
2
11
=5.5
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