Question

point A is chosen on Y axis in such a way that ABC is an equilateral triangle.The base BC of the ABC is shown in the figure.find the coordinates of i)the mid point of BC.ii)the area of the triang.iii)the vertices of a triangle.

Answer 1

Answer:

i) (0,0)

ii) 7.79 sq. units

iii) A(0,1.7)

    B(-3,0)

     C(3,0)

Step-by-step explanation:

Answer 2

Answer:

I am assuming O as (0, 0)

1) O is mid point /coodinates are (0, 0)

Point C lies on x axis so it would (3, 0) and point B will be(-3, 0) as O is mid point

(as 6/2=3)

Now we know AC = 6 units as triangle is Equilateral and OC =3 units

2) By Pythagoras theorem

OA^2 + OC^2 = AC^2

so OA =√AC^2 - OC^2

OA =√6^2 - 3^2

OA = √36-9

OA = 5

and point A lies on y axis so x coordinate is 0

i:e: point coordinates are (0, 5)

3) Area of triangle will be 1/2 base * height

=1/2 6*5

=15 unit^2

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