Question

point A lies in the exterior of a circle with center P and radius 8 cm tangent from A touches the circle at B . if AB = 15cm . find PA​

Answer 1

Answer

Given,

PB (radius) = 8 cm

AB = 15 cm

To find ,

PA

Solution ,

PA = PB + BA

PA = 8 + 15

PA = 23

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Answer 2

Answer: 17

Step-by-step explanation:

GIVEN:   AB= 15cm

              BP=8cm

              PA=?

By pythagoras theorem

$PA^{2}$ =$BP^{2} + BA^{2}$

$PA^{2} = 8^{2} + 15^{2}$

$PA^{2}=225+64\\PA^{2}=289\\PA=\sqrt{289} \\\\PA=17$