Point A lies on the line segment PQ joining P(6, -6) and Q(-4, -1) in such a way that PS/PQ = 2/5. If point P also lies on the line 3x + k(y + 1) = 0, the value of k is
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Answer:
Step-by-step explanation:
Let the point A(x,y) which lies on line joining P(6,−6) and Q(−4,−1) such that PA/PQ=2/5
Line segment PQ is divided by the point A in the ratio 2:3.
Step 1: Find coordinates of A(x,y)
x=
m
1
+m
2
m
1
x
2
+m
2
x
1
x=(2(−4)+3(6))/(2+3)
=(−8+18)/5
=10/5=2
y=
m
1
+m
2
m
1
y
2
+m
2
y
1
y=(2(−1)+3(−6))/5
=(−2−18)/5
=−20/5
=−4
Step 2: Point A also lies on the line 3x+k(y+1)=0
3(2)+k(−4+1)=0
6−3k=0
or k=2.
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