Question

point c is called a mid point of a line segment AB. prove that every line segment has one and only one mid point

Answer 1

wait....................

Answer 2

$\huge\star{\purple{\underline{\underline{\tt{Explanation:}}}}}$

______________________________

Let, AB be the line segment

Assume that points P and Q are the two different mid points of AB.

Now,

∴ P and Q are midpoints of AB.

Therefore,

AP=PB and AQ = QB.

also,

PB + AP = AB (as it coincides with line segment AB)

Similarly, QB + AQ = AB.

Now,

Adding AP to the L.H.S and R.H.S of the equation AP=PB

We get, AP + AP = PB + AP (If equals are added to equals, the wholes are equal.)

⇒ 2 AP = AB — (i)

Similarly,

$\leadsto$2 AQ = AB — (ii)

From (i) and (ii), Since R.H.S are same, we equate the L.H.S

$\leadsto$2 AP  = 2 AQ (Things which are equal to the same thing are equal to one another.)

⇒ AP = AQ (Things which are double of the same things are equal to one another.)

Thus, we conclude that P and Q are the same points.

This contradicts our assumption that P and Q are two different mid points of AB.

$\leadsto$Thus, it is proved that every line segment has one and only one mid-point.

$\large\star{\tt{\pink{\underline{Hence\:Proved.}}}}$