Question

Point charges and have been placed at marks 1, 2, 3, 4, 5, …,12 respectively on the circular dial of a clock. The electric field intensity at the centre of the dial if distance of each charge from the centre is r is

Answer 1

Answer:

ANSWER

The net electric field due to the oppositely faced charges would be in the direction of -7q, -8q, -9q, -10q, -11q and -12q and the magnitude of these charges would be -6q each.

The resultant of -10q, -11q and -12q would point in the direction of -11q and the resusltant of -7q, -8q and -9q would point in the direction of -8q.

Now finally the resultant of -11q and -8q would point in the direction of 9:30.

Thus the answer is 9.

Answer 2

Answer:

Point charges –q,2q,–3q,q,–q,2q,–3q,q,–q,2q,–3q, and q have been placed at marks 1,2,3,4,5..... 12 respectively on the circular dial of a clock. Find the electric field intensity at the centre of the dial if distance of each charge from the centre is r....