Question

point charges of 3 into 10 power minus 9 c r situated at each of three corners of a square whose side is 15 CM the magnitude and direction of electric field a

Answer 1

Electric field due to adjecent corner is given by:E = kqrwhere r is the side of the squareq is the charge on the corner.resultant electric is given by:R = E2+E2−−−−−−−√R = 2√Enow this resultant electric field and electric field due to diagonally opposite charge , are in same direction.E net = R+kqxx = 2√rE net= 2√kqr+kq2√r = kqr(32√) = 9×109×3×10−9×315×10−2×1.414 = 381.89 V/m