Question

point D and E are the midpoints of side ab and side AC of ∆ ABC surpectively .point F in on ray CO such that ED=DF. prove that rectangleAFBE is a parallelogram for this example. write ‘given’ and to ‘prove’ and complete the proof given below.​

Answer 1

Given:

ABC is a triangle, D & E are the respective mid points of AB &AC.

O is any point on BC, P & Q are mid points of OB & OC respectively.

To find:

Type of quadrilateral of DEQP.

Solution:

In ΔABC,D&E are the respective mid points of AB & AC. 

∴DE∥(BCorPQ)   ....(1)

Again in ΔABO,P&D are the respective mid points of AB & BO

∴DP∥AO    ... (2) 

Similarly, in ΔACO,EQ∥AO    ...(3)

∴ From (2) & (3), we get 

DP∥EQ    ... (4)

∴ From (1) & (4), we have

DE∥PQ and DP∥EQ

So, DEQP is parallelogram.

Answer 2

The provided Attachment is the correct solution and it is verified by my subject tr....