Point E bisects side CD of parallelogram ABCD and CF intersects DA produced at G such that CF|AE, where F is a point on AB. The value of AD x GF - CF x AG is
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In △ABE and △CFB,
∠ABE=∠CFB (Alternate angles)
∠BAE=∠BCF (opposite angles of a parallelogram)
∴ By AA criterion of similarity, △ABE ∼ △CFB
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