Question

Point M is given by (0,−7) and the line joining AB has equation −x−y+3=0 Find the equation of the line perpendicular to AB, passing through M. #1 y=x−7 #2 y=x+7 #3 y=−x+7 #4 y=−x−7

Answer 1

Answer:

ratio is 2:3 that m:n

now point that divides AB is (

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

x_1=0,x_2=-5,y_1=4,y_2=9

=(−2,6)

is the point

slope of AB is

−5

9−4

=−1

slope of line perpendicular to line AB is 1

equation of line perpendicular to line AB and passing through (−2,6)

is (y−6)=1(x+2)

x−y+8=0

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