Question

Point o(-2,3) is the center of the circle that passes through the origin of the coordinate system. The equation of the circle is: :​

Answer 1

Answer:

2 is answer okk

Step-by-step explanation:

hope it helps

Answer 2

Answer:$(x+2)^{2} +(y-3)^{2} = 13$

Step-by-step explanation:

The center of the circle is (-2,3)

The circle passes through origin (0,0)

The radius is thus the distance between the two points and is obtained as follows:

r = $\sqrt{(-2-0)^{2}+(3-0)^{2} } }$ = $\sqrt{13}$

The equation of a circle is obtained as follows:

$(x- a)^{2} +(y-b)^{2} = r^{2}$

where a and b are the co-ordinates of the radius i.e. (a,b)

In this case     a = -2    and  b =3

Therefore the equation of the circle is:

$(x--2)^{2} +(y-3)^{2} = (\sqrt{13} )^{2}$

Simplifying

$(x+2)^{2} +(y-3)^{2} = 13$