Question

Point O is the centre if the circle . Find the value of angle ACP if angle POB=90°
O isthe centre of circle
Angle POB =_____
ANGLE AOP =90. (_______)
MAJOR OF ARC ADP =_______
ANGLE ACP=______
Fill in the blanks

Answer 1

Answer:

We know that ∠ACB=∠PCB

In △PCB

Using the angle sum property

∠PCB+∠BPC+∠PBC=180

We know that ∠APB and ∠BPC are linear pair

By substituting the values

∠PCB+(180-110)+25

=180

On further calculation

∠PBC+70+25

=180

∠PCB+95

=180

By subtraction

∠PCB=180

o

−95

So we get

∠PCB=85

We know that the angles in the same segment of a circle equal

∠ADB=∠ACB=85

Therefore, the value of ∠ADB is 85

solution

mark me brainliest please!!!!!