Question

» Point o is the centre of the
circle of radius 25cm.
chord AB is of length 40cm.
Find its distance from the
Centre.
​

Answer 1

$\huge{\red{\mathtt{\underline{Answer:}}}}$

r = 25 cm

Length of cord = 40 cm

Perpendicular from center to cord bisect the cord.

Let it bisect it at point C .

In triangle AOC ,

Where C = 90° .

By Pythagoras theorem ,

AO² = AC² + OC²

$\boxed{AO \:is \:radius}$

25² = 20² + OC²

√625 - 400 = OC

OC = √225

OC = 15 cm

Hence distance from its cord is 15 cm .