Point of intersection of lines 2.r + y-3 = 0 and 3.r + 5y-7 = 0 lies in Quadrant
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2r + y - 3 =0 and 3r + 5y - 7 = 0
Multiply 1st eq by 5 and subtract from 2nd eq
you get r = 8/7
put this value of r in any eq you get y = 5/7
Since both r and y are positive, the point lies in 1st quadrant
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