Question

point of intersections of normals at points (4,a) and (b,2) to the parabola y^2=4x (ab>0) is?

Answer 1

Step-by-step explanation:

Given that normal intersect at point A,B and C on parabola y 2 =4x

The parabola intersect at P(h,K)y 2 =4x,h→x,K→y.

∴x=y 42i.e,2ydxdy =4

⇒ dxdy= y2

Equation of normal parring through (h,K)

x−x 1y−y 1 = x−y−K = dy−1

By solving ,and substituting values of (h,K)→(x,y)

x+y=1

Answer 2

Answer:

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