Question

point of object is placed in air in front of spherical surface of Glass with the convex surface towards if the distance between object and space is 25 and radius of curvature is 5 cm

Answer 1

Given :
magnification=m=-4[since it is real and magnified]
v= 60cm
object distance=u=?
magnification =m=V/u
u= 60/-4 =-15cm

Focal length=f=?
f=1/v - 1/u
=1/60 +1/15
=4+1/60
=5/60
f=60/5
=12cms

∴ Foal length of convex lens=12cm

Power=P=?
p=1/f (in m)
=100/f ( in cm)
=100/12
=+8.33 Diopters
∴ P=+8.3 D

Answer 2

A point object is placed in air in front of a spherical surface of a glass with the convex surface towards the object.If the distance between object and the surface is 25 cm and the radius of curvature of the surface is 5 cm , find the position of the image . ( refractive index of glass=1.5)

GIVEN

diagram.

air Π1 (______________

___.o_______.p(_____.c______.i___

(______________

Given.

u= po= -25cm

r = pc= 5cm

Π1 = 1

Π2 = 1.5

Π1/v - Π2/u = Π2-Π1/r

=1.5/v - 1/(-25) = 1.5-1/5

=1.5/v + 1/25 = 0.5/5 = 5/50 = 1/10

= 1.5/v = 1/10 - 1/25

= 5 - 2 / 50 = 3/50

= v/1.5 = 50/3

=V = 50 × 1.5/ 3

= 50/2

V= 25cm

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