Question

point on the x axis which is equidistant from (2,5) and (-2,9)

Answer 1

let D (x. 0) is the point on the x-axis which is equidistant from A (2, - 5) and B (- 2, 9)

⇒ AD = BD

using the distance formula



⇒ 

⇒ 

⇒ 

⇒ 

⇒ 

⇒ x = -7

hence D (-7, 0) be the point on x-axis which is equidistant from A (2, -5) and B (-2, 9).

Answer 2

(-7,0) is equidistance (2,5) and (-2,9)