Question

point out the type of error in the following program:

#include <iostream>
using namespace std;
int main()
{
int h= 10 ; w = 12
cout<<"Area of rectangle" <<h+w
}​

Answer 1

Answer:

//Program to receive two integer numbers and display their sum

#include <iostream>

using namespace std; int main()

{

     int num1, num2, sum;

     //variables num1, num2, and sum are declared as integers

     cout << "\n Enter Number 1: ";

     cin >> num1;

     cout << "\n Enter Number 2: "; cin >> num2;

     sum = num1 + num2;

     cout << "\n The sum of " << num1 << " and " << num2 << " is " << sum;

}

Illustration 9.2: C++ Program to accept any character and display its next character

#include <iostream>

using namespace std;

int main()

{

     char ch;

     cout << "\n Enter a character: ";

     cin >> ch;

     ch = ch + 1;

     cout << "\n The Next character: " << ch;

}

The output produced by the program will be

Enter a character: A

The Next character: B

Explanation:

Answer 2

Answer:

In the given program there are two syntax errors.

Explanation:

Consider the following given instruction

int h= 10 ; w = 12

The correct syntax for this instruction is :

int h=10,w=12;

or

int h=10;

int w=12;

In C++ a ‘;’ indicates end of a single instruction . Hence ( int h=10;) is an instruction and variable w is undefined variable which will raise an syntax error.

Another syntax error will be generated in the following instruction:

          cout<<"Area of rectangle" <<h+w

      a semicolon ‘;’ is expected at the end of this instruction to complete           it.

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