Point p(3,4,5) is at a maximum distance from
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Answer:
point p is at maximum distance from origin
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Point p(3,4,5) is at a maximum distance from x - axis
Given:
- Point p(3,4,5)
To Find:
- point p is at maximum distance from which axis ( complete Question)
Solution:
- Point on x axis is ( x , 0 , 0)
- point on y axis is ( 0 , y , 0)
- point on z axis is (0 , 0 , z)
Step 1:
Calculate Distance of point Point p(3,4,5) from x axis
√(x - 3)² + (0 - 4)² + (0 - 5)²
x = 3 for perpendicular distance
√(3 - 3)² + 16 + 25
= √41
Step 2:
Calculate Distance of point Point p(3,4,5) from y axis
√(0 - 3)² + (y- 4)² + (0 - 5)²
y = 4 for perpendicular distance
= √34
Step 3:
Calculate Distance of point Point p(3,4,5) from z axis
√(0 - 3)² + (0- 4)² + (z - 5)²
z = 5 for perpendicular distance
= √25
= 5
Maximum distance is √41 from x axis
Point p(3,4,5) is at a maximum distance from x - axis
(Although your Question is incomplete but complete Question is Point p(3,4,5) is at a maximum distance from which axis)
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