Question

Point P(-(a-b)², (1-a)²) lies in which quadrant, where a and b are not equal to 1​

Answer 1

Answer:

2nd quadrant

Step-by-step explanation:

here x coordinate is negative as

(a-b)² >0=> -(a-b)²<0

And y coordinate is positive as

(1-a)² >0

So the point P lies in 2nd quadrant.

hope it will help you.