Question

Point P divides the line segment joining the points A(2,1) and B(5,-8) such that AP : AB= 1 : 3 . If P lies on the line 2x-y+k=0 , then find the value of k.

Answer 1

Answer:

for p

x=((1*5)+(2*2))/3 y=((1*-8)+(2×1))/3

x=9/3 y=-6/3

x=3 y=-2

Step-by-step explanation:

put the value of p(x,y) in the equation 2x-y+k=0

through which p pass,we get the value of k.

2x-y+k=0

(2×3)-(-2)+k=0

6+2+k=0

8+k=0

k= -8

hope u may got it

so plz follow me and mark thnxs to my answer and as a brainliest also