Point p divides the line segment joining the points a(2 1) and b(5 -8) such that ap/ab =1/3 if p lies on the line 2x-y+k =0 find the value of k
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given
ap/pb = 1/3
If p divides internally
m = 1, n = 3
coordinates of p
= (5*1 + 2*3)/(1+3), (-8*1 + 1*3)/(1+3)
= (5 + 6)/4, (-8 + 3)/4
= 11/4, -5/4
since this point lies on 2x - y + k = 0
2*(11/4) - (-5/4) + k = 0
17/4 + k = 0
k = -17/4
2. If p divides externally
m= 1, n = 3
coordinates of P
= (5*1 - 3*2)/(1-3), (-8*1 - 3*1)/(1-3)
= (5 - 6)(-1), (-8 -3)/(-1)
= 1, 11
if this point lies on 2x - y + k = 0
2*1 - 11 + k = 0
k = 9
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