Point P divides the line segment joining the points A (2,1) and B (5,-8) such that AP/AB = 1/3 . If p lies on the line 2x-y+k=0, find the value of k
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hii it is not clearly question
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Step-by-step explanation:
given AP:AB-1:3
SO,AP:PB=1:2
GIVEN THAT P is lie on 2x-y+k=0
2(3)-(-2)+k=0
⇒6+2+k=0
⇒8+k =0
⇒k=-8
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