point P divides the line segment joining the points A(2,1)and B,(5,-8) such that AP/AB=1/3.If 2 lies on tje line 2x-y+k=0 .Find the value of k
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We have,
ABAP=31⇒AP+PBAP=31⇒3AP=AP+BP
⇒2AP=BP
⇒BPAP=21
So, P divides AB in the ratio 1:2.
∴CoordinatesofPare(1+21×5+2×2,1+21×−8+2×1)=(3,2)
Since,P(3,2) lies on the line 2x−y+k=0.
∴2×3−2+k=0⇒k=−4
TYPE III ON DETERMINATION OF THE TYPE OF A GIVEN QUADRILATERAL
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