Math, asked by dilchan, 4 months ago


Point P divides the line segment joining the
points A (2,1) and B(5,-8) in 1:2 and P is also
lies on the line
2x-y+k=0 Find the
value
Of k.

Answers

Answered by llallyjk
0

Answer:

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Answered by NRonit
1

Step-by-step explanation:

We know that by section formula, the co-ordinates of the points which divide internally the line segment joining the points (x1,y1) and (x2,y2) in the ratio m:n is

(x,y)=(m+nmx2+nx1,m+nmy2+ny1)

We have,

ABAP=31⇒AP+PBAP=31⇒3AP=AP+BP

⇒2AP=BP

⇒BPAP=21

So, P divides AB in the ratio 1:2.

∴CoordinatesofPare(1+21×5+2×2,1+21×−8+2×1)=(3,2)

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