Point P divides the line segment joining the
points A (2,1) and B(5,-8) in 1:2 and P is also
lies on the line
2x-y+k=0 Find the
value
Of k.
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Answer:
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Step-by-step explanation:
We know that by section formula, the co-ordinates of the points which divide internally the line segment joining the points (x1,y1) and (x2,y2) in the ratio m:n is
(x,y)=(m+nmx2+nx1,m+nmy2+ny1)
We have,
ABAP=31⇒AP+PBAP=31⇒3AP=AP+BP
⇒2AP=BP
⇒BPAP=21
So, P divides AB in the ratio 1:2.
∴CoordinatesofPare(1+21×5+2×2,1+21×−8+2×1)=(3,2)
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