Question

Point P divides the line segment joining the points A(2, 11) and B(5, -B) such that AP/AB =1/3 If P lies on the line 2x-y+k= 0, find the value of k

Answer 1

Answer:

Step-by-step explanation:

Point P divides the line segment joining the points A(2, 11) and B(5, -B) such that AP/AB =1/3 If P lies on the line 2x-y+k= 0, find the value of k

AB = 3AP

AB = AP + BP

3AP = AP + BP

2AP = BP

AP/BP = 1/2

AP: BP :: 1:2

Coordinate of P

= (1Bx + 2Ax)/(1+2) , (1.By + 2Ay)/(1 +2)

= (5 + 4)/3 , (-B + 22)/3

= 3 , (-B + 22)/3

2x - y + k = 0

6 + (B -22/3) + k = 0

K =.22/3 - 6 - B/3

K = (4 - B)/3