Point P is 5 m south of point A. Point T is 8 m east of point Q. Point Z is 4 m west of point V. Point P is 6 m
west of point B. Point V is 6 m south of point T. Point Q is 4 m south of point B.
A person starts from point B in north direction. Walks for 6 m and reaches point C, takes a right turn walks for
5 m reaches point F. Again he takes a right turn, walks for 3 m, reaches point H, now takes a left turn, reaches
point K, now takes a final right turn to reach point T. Find the area enclosed by points B, Q, T, K, H, F and C.
(a) 58 m2
(b) 65m2
(c) 71 m2
(d) 76 m2.
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71 m2 is the your question answer
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Answer:
The area enclosed by points B, Q, T, K, H, F and C is 71m²
Step-by-step explanation:
Find the attached diagram for illustration.
As the distance between Q and T is 8m.
The distance between C and F and H and K is parallel to Q and T,
=> CF + HK = QT
=> 3m + HK = 8m
=> HK = 8m - 3m = 5m
As the distance between Q and C is 10m.
The distance between k and F and T and K is parallel to Q and C,
=> FH + KT = CQ
=> 3m + KT = 10m
=> HK = 10m - 3m =7m
Therefore, the area enclosed by points B, Q, T, K, H, F and C.
= The area of 1 and 2
=> 5m*10m + 3m*7m
=> 50m² + 21m²
=> 71m²
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