point P is in exterior of the circle with centre O if AP=4cm find the length of BP
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Step-by-step explanation:
From figure,
CA is perpendicular to AP and CB is perpendicular to BP
Again AC = BC = 4 (radius of the circle)
Also AP = PB = (Tangents from point P)
So, BPAC is a square.
=> AP = PB = BC = CA = 4 cm
So, length of tangents are 4 cm each
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