Question

Point P is the centre of the circle and AB is a diameter Find the co-ordinate
point B if coordinates of point A and P are (2. -3) and (-2, 0) respectively​

Answer 1

Answer:

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A line intersects the y-axis and x-axis at the points P and Q, respectively. If (2, –5) is the mid-point of PQ, then the coordinates of P and Q are, respectively

A:(0, 4) and (– 10, 0)

B:(0, – 10) and (4, 0)

C:(0, 10) and (– 4, 0)

D:(0, – 5) and (2, 0)

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Chapter 7.Coordinate Geometry

Question NO.438

Question

A line intersects the y-axis and x-axis at the points P and Q, respectively. If (2, –5) is the mid-point of PQ, then the coordinates of P and Q are, respectively

A:(0, 4) and (– 10, 0)

B:(0, – 10) and (4, 0)

C:(0, 10) and (– 4, 0)

D:(0, – 5) and (2, 0)

Answer

Let the coordinates of P (0, y) and Q (x, 0).

So, the mid - point of P (0, y) and Q (x, 0) = M

Coordinates of M =

Mid - point of a line segment having points (x1, y1) and (x2, y2)

=

Given,

Mid - point of PQ is (2, - 5)

= 4 = x + 0

x = 4

= - 10 = y + 0

- 10 = y

So,

x = 4 and y = - 10

Thus, the coordinates of P and Q are (0, - 10) and (4, 0)

Therefore the choice is: B

Answer 2

Explanation:

as p is the center of the circle it divides the line in two equal part I.e AP=BP

let co coordinates of A be x1,y1 ,P x,y ,Bx2,y2

therefore, by mid point them.

x=x1+x2/2

2=-2+x1/2

2×2=-2+x1

4=-2+x1

4+2 =x1

x1=6

y=y1+y2/2

-3=0+y2/2

-3×2=y2

-6=y2

therefore the coordinates of B are 6,-6