point P is the midpoint of seg CD. if CP is 2.6,find I (CD)
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Since P is the midpoint of seg CD.
Therefore seg CP ≅ seg PD, i.e. seg CP = seg PD ……….(i)
Also, we know that
For any three-distinct collinear points P, Q and R, the point Q is said to be in between P and R if
d (P, Q) + d (Q, R) = d (P, R), or
l (PQ) + l (QR) = l (PR)
So, seg CD = seg CP + seg PD
⇒ seg CD = 2 seg CP [Using (i)]
⇒ seg CD = 2 × 2.5 = 5
So, seg CD = 5
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