Point p lies on a circle with centre o and A is a point of the tangent through P if PA = 7CM and OA = 25cm, find the diameter of the circle.
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Solution :-
from image we get,
- O = centre of circle .
- OP = radius of circle.
- OA = 25 cm .
- PA = 7 cm.
we know that,
- The tangent at any point of a circle is perpendicular to the radius through the point of contact .
so,
- ∠OPA = 90° .
then in right angled ∆OPA,
→ OP = √(OA² - PA²) { By pythagoras theorem .}
→ OP = √(25² - 7²)
→ OP = √(625 - 49)
→ OP = √(576)
→ OP = 24 cm.
therefore,
→ Diameter of the circle = 2 * radius = 2 * 24 = 48 cm. (Ans.)
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