Point P Lies on side BC of parallelogram ABCD such that BP = CP and AP bisects ZBAD. The incorrect option can be
AD = 2AB
ZCDP = LDAP
AP = DP
LAPD = 90°
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Answered by
12
Answer:
the figure,
1 = 2 (given)
But 2 = 3 (alternate interior angles)
1 = 3
AB = BP (sides opp. to equal angles are equal)
But AB = CD (opposite sides of ||gm)
CD = BP
CD = BC (Since, P is the mid-point of BC)
2CD = BC
2CD = AD (Since, BC = AD)
Step-by-step explanation:
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Answered by
0
Answer:
4th option
Step-by-step explanation:
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