Question

Point p lies on the exterior of the the circle with center O. Tangent through P touch the circle at A and B. If the angle formed by PA and PB is 80 degrees, then angle POA=_______________

Answer 1

Answer:

:here AOBP is a cyclic qadrilateral

and we know that the sum of opposite angles of a cyclic

quadrilateral is 180 so angle AOB+angleAPB=180

                                       angle AOB+80=180

                                       angleAOB=180-80

                                        angle AOB=100

join PO , PO bisects angle AOB and angle APB

Hence angle POA=100/2

            angle POA=50          

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Answer 2

ask from google I have a look forward.