Question

Point point P divides the line segment joining the point A 2 3 and B 5, -8 such that AP upon a b is equal to 1 upon 3 if P lies on the line 2 x minus y + K is equal to zero find the value of k

Answer 1

Answer:k=-21/4

Step-by-step explanation: In points A(2,3) ; B(5,-8) the line joined is divided in the ratio

1:3. So,m=1 and n=3.

By using section formula,

mx"+nx'/m+n , my"+ny'/m+n

1*5+3*2/1+3, 1*(-8)+3*3/1+3

5+6/4, -8+9/4

11/4,1/4

Therefore, the point which divides the line segment AB is (11/4,1/4)

In the equation 2x-y+k=0,the value of x and y satisfies.

Hence, in the eqn, x=11/4 Andy=1/4.

2(11/4)-1/4+k=0

11/2-1/4+k=0

21/4=-k

Therefore , k=-21/4