Point R divides PQ in the ratio 2:3. If thr coordinates of P are (0,0) and that of R are (10,-8) then find the coordinates of Q.
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Answer:
50/3. -40/3
Step-by-step explanation:
P= ( 0 ,0)
Q= ( x, y)
R = (10, -8)
x=( mx1 + n x2) /m+n
y= (my1 + n y2) /m+n
10= (2x0 h 3xX )/ 5
50= 3X
X= 50/3
similarly
-8= (2x0 h 3xY )/ 5
-40= 3Y
-40/3= Y
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