Math, asked by desaiswaradakaushal, 9 months ago

Point S is is any point on side QR of triangle PQR prove that PQ + Q R + RP is greater than 2 PS

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Answered by khushh213

4

Step-by-step explanation:

PQ+QS>PS (SUM OF TWO SIDES IS GREATER THEN THE THIRD SIDE )

SIMILRLY PR+RS>PS

ADDING BOTH

PQ+QS+PR+RS>PS+PS

PQ+PR+QR>2PS

HENCE PROVED

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