Question

Point S is the midpoint of seg TR. If TR=17, find l(TS).​

Answer 1

Answer:

b2+c2=2a2+2d2

Comparing the attached triangle, with the given triangle,

PQ = 11,

PR = 17,

PS = 13

Applying Apollonius's Theorem,

\begin{gathered}\Rightarrow PQ^{2}+PR^{2}=\frac{QR^2}{2}+2PS^2\\\\\Rightarrow

(11)^{2}+(17)^{2}=\frac{QR^2}{2}+2(13)^2\\\\

\Rightarrow QR^{2} = 2(11^2+17^2-2(13)^2)\\\\

\Rightarrow QR^{2} = 2(121+289-338)=2\times 72\\\

\Rightarrow QR^{2} = 144\\\\

\Rightarrow QR=12\end{gathered}

⇒PQ2+PR2=2QR2+2PS2⇒(11)2+(17)2=2QR2

+2(13)2⇒QR2=2(112+172−2(13)2)⇒QR2=2(121+289−

338)=2×72⇒QR2=144⇒QR=12

..Therefore, the value of QR is 12

Answer 2

Answer:

"Let the required number be x.

Let the required number be x.

Let the required number be x. According to the condition, we get

Let the required number be x. According to the condition, we getx+5= 10

Let the required number be x. According to the condition, we getx+5= 10Subtracting 5 on both the sides, we get

Let the required number be x. According to the condition, we getx+5= 10Subtracting 5 on both the sides, we getx + 5 - 5 = 10 - 5

Let the required number be x. According to the condition, we getx+5= 10Subtracting 5 on both the sides, we getx + 5 - 5 = 10 - 5→ x = 5"