point T is -56/9,3 divides seg AB in the ratio 7:2 and coordinate of B are -6,-7 then find the coordinate of point A??
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Let coordinates of point A be(x,y)
T=(7×-6+2x/7+2,7x-7+2y/7+2) (section formula)
=(-42+2x/9,-49+2y/9)
But t=(-56/9,3)
=> -42+2x/9=-56/9
=>-42+2x=-56
=>2x=-56+42
=>x=-14/2
=-7
Also,-49+2y/9=3
=>-49+2y=27
=>2y=27+49
=>y=76/2
=38
A =(-7,38)
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